Thursday, July 31, 2014
You can simplify the arrays construction, too: (with slight reformatting of the arrays output)
irb2.1.1> arrays = Array.new(3) { Array.new }
#2.1.1 => [[], [], []]
irb2.1.1> 100.times {|id| arrays.sample.push(id) }
#2.1.1 => 100
irb2.1.1> arrays
#2.1.1 => [[0, 2, 6, 8, 9, 11, 14, 16, 17, 18, 22,
24, 29, 31, 37, 42, 47, 49, 53, 54, 57,
58, 60, 68, 69, 73, 75, 79, 80, 81, 83,
88, 91, 94, 95, 96],
[1, 3, 12, 13, 20, 25, 26, 28, 33, 34,
38, 39, 43, 44, 48, 50, 52, 59, 63, 65,
70, 72, 74, 77, 78, 82, 86, 87, 89, 97],
[4, 5, 7, 10, 15, 19, 21, 23, 27, 30,
32, 35, 36, 40, 41, 45, 46, 51, 55, 56,
61, 62, 64, 66, 67, 71, 76, 84, 85, 90,
92, 93, 98, 99]]
irb2.1.1> arrays.map(&:size)
#2.1.1 => [36, 30, 34]
On 2014-Jul-31, at 12:00 , Eric Saupe <ericsaupe@gmail.com> wrote:
I knew there would be a nice simpler Ruby way. I love the second solution, Rob. Below is the updated example.id = 100
arrays = [Array.new, Array.new, Array.new]
arrays.sample.push(id)
On Thursday, July 31, 2014 8:45:33 AM UTC-6, Rob Biedenharn wrote:On 2014-Jul-30, at 10:59 , Eric Saupe <eric...@gmail.com> wrote:To expand on what Scott is saying here is some code that gives an example of what he is referring to.id = 100
x = rand(1..3)
arrays = [Array.new, Array.new, Array.new]
selected_array = arrays[x]
selected_array.push(id)And to make it a bit more flexible, you could do:arrays = [ Array.new, Array.new, Array.new ]x = rand(arrays.size)arrays[x].push(id)or even:arrays = [ Array.new, Array.new, Array.new ]arrays.sample.push(id)-Rob
On Tuesday, July 29, 2014 8:05:16 PM UTC-6, Scott Ribe wrote:On Jul 29, 2014, at 7:33 PM, Dave Castellano <li...@ruby-forum.com> wrote:
> Novice question:
>
> I need to assign an item id to one of 3 arrays randomly but can't figure
> out how to specify the correct array by combining "arr" and the randomly
> generated number...
>
> id = "100"
> x = rand(1..3)
>
> arr1 = Array.new
> arr2 = Array.new
> arr3 = Array.new
>
> selected_array = "#{'arr' + x}" *** Not sure how to do this ****
>
> selected_array.push(id)
>
While you could append the name and eval, that's not really a clean approach. Just use an array of arrays. Or if else...
--
Scott Ribe
scott...@elevated-dev.com
http://www.elevated-dev.com/
(303) 722-0567 voice
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