Ruby on Rails

On Mon, Feb 27, 2012 at 5:05 PM, Bill Walton <bwalton.im@gmail.com> wrote:
> On Mon, Feb 27, 2012 at 4:51 PM, Rodrigo Ruiz <rodrigo.ruiz7@gmail.com> wrote:
>> Ya, that is what I used (with sort), I was just wondering if there is a
>> native way like:
>
> No need to waste cycles like that.  Array math will do fine.
>
>> a = [1, 4, 2]
>> b = [2, 1, 4]
>>
>> a.has_same_elements_as(b)
>
> ruby-1.9.2-p290 :001 > a = [4,1,2]
>  => [4, 1, 2]
> ruby-1.9.2-p290 :002 > b = [1,2,4]
>  => [1, 2, 4]
> ruby-1.9.2-p290 :003 > b - a
>  => []
> ruby-1.9.2-p290 :004 > a - b
>  => []
>
>
> HTH,
> Bill

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