Ruby on Rails

Hi Jim..
thanks..
looks good now.. I had a mistake in another model..so the grouping was not correct.

my god.. what a trip sometimes..

Werner

Am Freitag, 25. Januar 2013 14:50:53 UTC+1 schrieb jim:

On Fri, Jan 25, 2013 at 9:42 PM, Werner <webagent...@googlemail.com> wrote:

Well.. I cant get it working

Try to explain it again..

db_table:
week_id, project_id, user_id, hour
ex. =>
33, 1, 1, 10
33, 4, 1, 20
33, 1, 2, 0
34, 1, 2, 15
34, 1, 1, 0


So, user with the id 1 worked 10 hours in week 33 and 20 in the week 33, but other project
I want to show all hours summed up per week per user
row1(user1) => week 33 => 30, week 34 => 0
row2(user2) => week 33 => 0, week 34 => 15

Step one:
I want one row per user, so I group:
@hours = HourUser.all.group_by(&:user_id)

view:
@hours.each do |user, weeks|

gives me each user in one <tr>
within this row, each week one cell

<% weeks.group_by(&:week_id).each do |week, hours| %>
<td><%= hours.map(&:hour).sum %>

Shows the hours but not summed up. Instead I get :
row 1 =>  ...10.. and does not stop the row but starts again with ... 20...
row 2 =>  ...0 15

so this is your remaining problem right?  I think the hour column is

a string which results to a concat of the values instead of simple

addition.  try hours.map { |h| h.hour.to_f }.sum

 

How to? Do I also have to group otherwise..?
Thanks for support.


























Am Donnerstag, 24. Januar 2013 16:01:06 UTC+1 schrieb jim:

On Thu, Jan 24, 2013 at 10:38 PM, Werner <webagent...@googlemail.com> wrote:

Jim..sorry.. not my day...
have to contemplate about your solution.

I wonder..

HourUser.includes(:user).where.....group_by { |h| h.week_id }

<% @hours.keys.sort.each do |h| %>
 <%= @hours[h].collect(&:hour).sum %></td>
<% end %>

is giving me what I want, just needs to be grouped by user_id

Thanks so far.

So given the current solution you have, you also want to group by user_id right?

so here's how it should go.

@hour_users = HourUser.all.group_by(&:week_id)

gives you a hash with week_ids as keys

@hour_users.each do |week_id, by_week|

  by_week.group_by(&:user_id).each do |user_id, hour_users|

    hour_users.map(&:hour).sum

  end

end

using my first suggestion

@hour_users = HourUser.sum(:hour, group: [:week_id, :user_id])

@hour_users.each do |(week_id, user_id), total_hours|

  # do something with week_id, user_id and total_hours

end

Good luck! 

Am Donnerstag, 24. Januar 2013 14:16:16 UTC+1 schrieb jim:

On Thu, Jan 24, 2013 at 7:55 PM, Werner <webagent...@googlemail.com> wrote:

Hi Jim.. thanks so far..

in the moment this is a bit too far for me.

Just remember that to get a certain value, you'll have to pass an array as the index

ie sums[[33,2]] to get 70

=> this is unclear
Pls. be so kind to explain the view part.

since the keys of the hash is an array, you need to use an array as the index to get a value

>> sums = { [33, 2] => 70, [34, 2] => 15, [35, 3] => 20 }

>> sums[34,2]

ArgumentError: wrong number of arguments (2 for 1)

from (irb):3:in `[]'

from (irb):3

>> sums[[34,2]] # 15

the keys are defined by the group option you passed to #sum, so if you pass as sql statement to

the group option, you'll get that as key. ie (postgre)

>> HourUser.sum(:hours, group: "week_id || ' --- ' || user_id", order: :user_id)

>> { '33 --- 2' => 70, '34 --- 2' => 15, '35 --- 3' => 20 }

hope this helps

 

Werner

Am Donnerstag, 24. Januar 2013 11:36:44 UTC+1 schrieb jim:

On Thu, Jan 24, 2013 at 4:35 PM, Werner <webagent...@googlemail.com> wrote:

Hi.. I need some support...

table:
week_id, user_id, project_id, hours
ex. =>
33, 2, 1, 10
34, 2,1,15
33, 2, 2, 20
35, 3, 1,20
etc.

Want to display a sum of hours per week_id per user_id
I have:

@hours = HourUser.includes(:user).group_by { |h| h.week_id }

@hours.keys.sort.each do |hour|
@hours[hour].collect(&:stunden).sum

Look at http://api.rubyonrails.org/classes/ActiveRecord/Calculations.html#method-i-sum

sums = HourUser.sum(:hours, group: [:week_id, :user_id], order: :user_id)

You'll end up with something like [33, 2] => 70, [34, 2] => 15, [35, 3] => 20

Just remember that to get a certain value, you'll have to pass an array as the index

ie sums[[33,2]] to get 70

 

Hours are summed up, but not sorted by user_id..
How to get that?

Thanks

Werner

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