Ruby on Rails
Friday, July 31, 2015
Message fields user_one and user_two concern me. Before I respond to your question, would you mind sharing the structure of your message and user tables?
Thanks, Liz
On Friday, July 31, 2015 at 1:53:08 AM UTC-4, nilayy...@gmail.com wrote:
-- Thanks, Liz
On Friday, July 31, 2015 at 1:53:08 AM UTC-4, nilayy...@gmail.com wrote:
I have a very simple question how can I convert mysql query as Raisl active record I am using find_by_sql but it only work for mysql when I move to heroku it doesn't work . Here is mysql query below .
@message3 = User.find_by_sql("SELECT u.id,c.m_id,u.name,u.email FROM messages c, users u WHERE CASE WHEN c.user_one = #{current_user.id} THEN c.user_two = u.id WHEN c.user_two = #{current_user.id} THEN c.user_one= u.id END AND ( c.user_one ='1' OR c.user_two ='1' ) Order by c.m_id DESC Limit 20")
I have tried different rules to run it and no success . I have used this code below :
@m1 = Message.joins(:user).select("u
sers.id ,messages.m_id,users.name ,users.email ,CASE WHEN messages.user_one =#{current_user.id} THEN messages.user_two =users.id WHEN messages.user_one =users.id THEN messages.user_two =1 END").where("messages.user_one = 1 OR messages.user_two = 1 ").limit(20).order(:m_id)But above code is not generating the correct result here I have two models user and message their relation is user has_many messages and messages belons_to user When I am using this code I am getting this result in json format with no error .
[{"m_id":55,"id":55,"name":"
Example User" ,"email":"ni...@jumpbook.in ","CASE WHEN messages.user_one =1 THEN messages.user_two =users.id WHEN messages.user_one =users.id THEN messages.user_two =1 END":0}]How can I use this query perfectly and why I am getting this result when I am using select function in this query is there anyone help me
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